Given:
exsinx=1 has two real roots → say x1 and x2
Apply Rolle’s Theorem:
Since f(x)=exsinx is continuous and differentiable, and f(x1)=f(x2), ⇒ There exists c∈(x1,x2) such that f′(c)=0
Compute:
f′(x)=ex(sinx+cosx)=0⇒tanx=−1 At this point, excosx=−1
At least one root
Not Available
Online Test Series, Information About Examination, Syllabus, Notificationand More.
Are you sure to delete this comment ?